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snow_lady [41]
2 years ago
6

Which expression is equivalent to (StartFraction a Superscript negative 8 Baseline b Over a Superscript negative 5 Baseline b cu

bed EndFraction) Superscript negative 3? Assume a not-equals 0, b not-equals 0.
a Superscript 9 Baseline b Superscript 6
a Superscript 9 Baseline b Superscript 12
StartFraction 1 Over a cubed b squared EndFraction
StartFraction a Superscript 29 Baseline b Superscript 6 Baseline EndFraction
Mathematics
2 answers:
Eddi Din [679]2 years ago
8 0

Answer:

its A, a^9 b^6

Step-by-step explanation:

right on edge 2020

leonid [27]2 years ago
8 0

Answer:

a

Step-by-step explanation:

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Find the quotient Write the remainder as a fraction 89,420÷27
goldfiish [28.3K]
3311.85185.... is the quotient. The fraction is 3311 23/27
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3 years ago
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Last summers, students who worked earned an average of $80 a week with a standard deviation of $12. What percentage of students
Roman55 [17]

Answer:

  • 2.28%

Step-by-step explanation:

<u>Given:</u>

  • μ = 80
  • σ = 12
  • x = 104

<u>Find z-score:</u>

  • z = (x - μ)/σ
  • z = (104 - 80)/12 = 2

Percent value corresponding to 2 as per z-table is 0.9772. This is corresponding to 97.72%.

<u>Percentage of students earned more than $104:</u>

  • 100 - 97.72 = 2.28
5 0
2 years ago
In a city school, 70% of students have blue eyes, 45% have dark hair, and 30% have blue eyes and dark hair. What is the probabil
Travka [436]

<u>Answer:</u>

The correct answer option is 43%.

<u>Step-by-step explanation:</u>

We are given that 70% of students have blue eyes, 45% have dark hair, and 30% have blue eyes and dark hair.

We are to find the probability of a student getting selected will have dark hair with blue eyes.

P(D|B) = P(D∩B) / P(B)

Substituting the given values in it to get:

P(D|B) = 0.3 / 0.7 = 0.428

Rounding it to the nearest whole percent we get:

0.428 × 100 = 42.8% ≈ 43%

4 0
3 years ago
Five less than the product of a number and-8 is -77
SVETLANKA909090 [29]

five less than the product of a number and-8 is -77

-8n -5 = -77

add 5 to each side

-8n = -72

divide by -8

n =9

5 0
3 years ago
Are the equations lxl – 3 = 7 and [x] = 10 equivalent?
zvonat [6]

They're not equivalent.

|x| (vertical bars) represents the absolute value of x. How it works is that it turns negative numbers positive but leaves 0 and positive numbers alone (hence it gets a number's distance from 0 on the number line).

[x] (square brackets) usually represents the floor function, which returns the largest integer that is less than or equal to x. (The floor of x can also be written as \lfloor x \rfloor --- it depends on what your textbook/source says).

To solve |x| - 3 = 7, you first transform it into the equivalent equation |x| = 10. Then by definition of absolute value, there are only two solutions for the first equation: x = 10 or x = -10.

[x] = 10 has infinitely many solutions. For example, the floor of 10 is 10, so [10] = 10, thus a solution for the second equation is x = 10

The floor of 10.1 is 10, so [10.1] = 10, thus another solution for the second equation is x = 10.1.

The two equations do not have the same solution set (as x = 10.1 does not solve |x| - 3 = 7 but solves [x] = 10), so they're not equivalent.

5 0
2 years ago
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