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Otrada [13]
3 years ago
9

The homeowner is worried about the work needed to maintain a grass lawn and flower beds, so she is now looking at some low-maint

enance materials.
She is considering artificial turf, which costs $15 per square foot to install, and gravel, which costs $3 per square foot. She may use a combination of the two materials in different parts of the yard. Her budget is still $3,000.



Here is a graph representing some constraints in this situation.



The graph shows a line going through (500,100).



In this situation, what does the point (500,100) mean?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

nsjsbdjdjdjdbdyshehdhjdkdhejdvgbshsvdjydjdhsdñ

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Find the domain of the function f(x) = – 1x^2 – 2x – 1
navik [9.2K]

Answer:

All real numbers.

Step-by-step explanation:

Since this is a quadratic function, that means the domain is all real numbers.

If you would like more help on math or other subjects for FREE, check out growthinyouth.org.

7 0
3 years ago
Calculate the x and y-intercept for the line:<br><br> y=-2x+8
Kryger [21]
<span>x-intercept, y = 0:
 -2x + 8 =0
 -2x = -8
    x= -8/-2 = 4<span> 

y-intercept, x =0
y = 8</span></span>
3 0
3 years ago
Best estimate for 7/8-6/11
adell [148]
Ummm we are allll gonna be dead cause Biden be da president
7 0
3 years ago
The vertices of a triangle are (-1,3) (6,3) and (-1,-4)
Travka [436]

Answer:

24.5 unit²

Step-by-step explanation:

Area of ∆

= ½ | x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂) |

= ½ | (-1)(3 -(-4)) + 6(-4 -3) + (-1)(3 - 3) |

= ½ | -7 - 42 |

= ½ | - 49 |

= ½ (49)

= 24.5 unit²

<u>Method 2:</u>

Let the vertices are A, B and C. Using distance formula:

AB = √(-1-6)² + (3-3)² = 7

BC = √(-6-1)² + (-4-3)² = 7√2

AC = √(-1-(-1))² + (4-(-3))² = 7

Semi-perimeter = (7+7+7√2)/2

= (14+7√2)/2

Using herons formula:

Area = √s(s - a)(s - b)(s - c)

here,

s = semi-perimeter = (14 + 7√2)/2

s - a = S - AB = (14+7√2)/2 - 7 = (7 + √2)/2

s - b = (14+7√2)/2 - 7√2 = (14 - 7√2)/2

s - c = (14+7√2)/2 - 7 = (7 + √2)/2

Hence, on solving for area using herons formula, area = 49/2 = 24.5 unit²

3 0
3 years ago
Read 2 more answers
Evaluate 11c3 and 11p4
In-s [12.5K]

_{n}C_{r} = \frac{n!}{r!(n-r)!}  \\ \\ _{11}C_{3}= \frac{11!}{3!*(11-3)!} =\frac{11*10*9*8*7*6*5*4*3*2*1}{3*2*1*8*7*6*5*4*3*2*1} =\frac{11*10*9}{3*2} =165 \\ \\_{11}C_{4}=\frac{11!}{4!(11-4)!} =\frac{11*10*9*8*7!}{4!*7!} =\frac{11*10*9*8}{4*3*2*1} =330

7 0
3 years ago
Read 2 more answers
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