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3 years ago

4/ (4/ 9) = (4/ 4)/ 9 true or false

1 answer:

5 0

False, moving the parenthesis works in certain problems like 1x(2x3)=(1x2)x3

but with division it must be perfect otherwise a simple percentage can ruin your whole division problem.

You might be interested in

The area of a rectangle increased by seven is the same as for less than twice the area of the rectangle. Right and solve an equa

never [62]

Answer:

11 Square Units

Step-by-step explanation:

Let A be the area of the Rectangle

First statement: The area of the rectangle is increased by seven, we have :

A+7

Second Statement: Four less than twice the area of the rectangle

Twice the Area=2A

Four less = 2A-4

Therefore:

2A-4=A+7

Collecting like terms

2A-A =7+4

A=11

The area of the rectangle is 11 Square Units.

7 0

2 years ago

What are the coordinates for a dilated triangle, A’B’C’, if the scale factor for the dilation is 0.75?

ycow [4]

Answer:

A’(–3.75, 0.75); B’(0, 1.5); C’(3, –1.5)

Step-by-step explanation:

Did this on edgenut and got it right

Hope this helps

6 0

2 years ago

Read 2 more answers

The qestion is the picture

lianna [129]

Answer:

-2/9

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Triangle ptg has side lengths of 18 27 cm and 13 cm what type of triangle is it

diamong [38]

Angle PTG = arccos((18^2 + 13^2 - 27^2) / (2 x 18 x 13)) = arccos(-236 / 468) = arccos(-0.5043) = 120 degrees.

The triangle is an obtuse triangle (because one of the angles is greater than 90 degrees) and a scalene triangle (because all the sides are not equal).

6 0

2 years ago

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The p

mash [69]

Answer:

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The probability that the mean height of an SRS of 10 young women exceeds 66.5 inches is ＿

normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(-99999999, 66.5, 64.5, 2.5)

normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(66.5, 99999999, 0, 1)

1 - normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 0, 1)

normalcdf(--99999999, 66.5, 64.5, 0.7906)

plz need help number 1 2 3 4 5 are pic

8 0

2 years ago