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Maslowich
2 years ago
10

Which expression represents the lateral surface area of the cone?

Mathematics
1 answer:
Setler [38]2 years ago
6 0

Answer:

π(6 cm) (10 cm)

Step-by-step explanation:

As we know that

The formula to calculate the lateral surface area of the cone is πrl

where

r denotes the radius i.e. 6 cm

l denotes the length i.e. 10 cm

So based on the above information

The expression that shows the lateral surface area of the cone is

π(6 cm) (10 cm)

Therefore the third option is correct

Hence, the same would be relevant

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Find A and B if the graph of Ax + By = 12 passes through (2,1) and is parallel to the graph of 2x - 7y = 3
Ivenika [448]

Answer:

24-21

Step-by-step explanation:

2×12=24 7×3=21 I started from 2×2 towards 2×12 when I got the answer and I started 7×1 towards 7×3

4 0
2 years ago
What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?
Anvisha [2.4K]

Answer:

y=-\frac{3}{2}x-\frac{9}{2}

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = \frac{y_2-y_1}{x_2-x_1}

m' = \frac{1+1}{3-0}

m' = \frac{2}{3}

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × \frac{2}{3} = -1

m = -\frac{3}{2}

Equation of the perpendicular line will be,

y=-\frac{3}{2}x+b

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = -\frac{3}{2}(-3)+b

b = -\frac{9}{2}=-4.5

Equation of the line will be,

y=-\frac{3}{2}x-\frac{9}{2}

3 0
3 years ago
-5(6p+1)=-25-5p+20-25p
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37 IS THE ANSWER IM NO YELLING LOL
4 0
3 years ago
Which statements are true regarding undefinable terms in geometry? Check all that apply.
Vanyuwa [196]
I do not have your choices but all the statements that I can think of is the following: A point in the x,y form has two dimensions, a plane has a definite beginning and end, the line has one dimension or length, and finally a point consists of an infinite set of the lines  <span />
7 0
3 years ago
Read 2 more answers
The area of sector A08 is 48x and m&lt;AOB = 270º. Find the radius of circle O.
Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ is the measure of the central angle of the circle. For us, that fills in as follows:

48\pi=\frac{270}{360}*\pi r^2 and manipulate it as follows:

r^2=\frac{(360)(48\pi)}{270\pi} the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ again is the measure of the central angle of the circle, 90°:

A_s=\frac{90}{360}(3.1415)(10)^2 which simplifies a bit to

A_s=\frac{1}{4}(3.1415)(100), giving us an area of

A_s=78.5375m^2. Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

A_t=\frac{1}{2}(10)(10) which is

A_t=50m^2

Subtract that from the area of the sector to get that the shaded area is 28.5 square meters, choice A.

4 0
3 years ago
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