Answer:
Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]
Step-by-step explanation:
We are given that a function
Interval [1,5]
The given function is defined on this interval.
Hypothesis of Mean Value Theorem:
(1) Function is continuous on interval [a,b]
(2)Function is defined on interval (a,b)
From the graph we can see that
The function is continuous on [1,5] and differentiable at(1,5).
Hence, the function satisfies the hypothesis of the Mean Value Theorem.
The <em>xy</em>-plane has a normal vector of 〈0, 0, 1〉, and any plane parallel to it will have the same normal vector.
Then the equation of the plane through (6, 3, 2) that is parallel to the <em>xy</em>-plane has equation
〈<em>x</em> - 6, <em>y</em> - 3, <em>z</em> - 2〉 • 〈0, 0, 1〉 = 0
==> <em>z</em> - 2 = 0
==> <em>z</em> = 2
Step-by-step explanation:
5(2h+8) <60
10h +40< 60
10h + 40-40 < 60-40
10h < 20
10h/10 < 20/10
h < 2
Answer:
197 leis left over
Step-by-step explanation:
14 times 212 = 2968
2968/30 = 98.93
212 times 0.93 = 197
98 packages and 197 leis left over
-2+6x+4+4x
=2+10x
hope it helps
