<h2>
Answer:</h2>
∠LMN is a right angle
<h2>
Step-by-step explanation:</h2>
If we want to prove that two right triangles are congruent by knowing that the corresponding hypotenuses and one leg are congruent, we begin as follows:
- Since two legs are congruent and we know this by the hash marks, then the triangle ΔLKN is isosceles.
- By definition LN ≅ NK
- If ∠LMN is a right angle, then MN is the altitude of triangle ΔLKN
- Also MN is the bisector of LK, so KM ≅ ML
- So we have two right triangles ΔLMN and ΔKM having the same lengths of corresponding sides
- In conclusion, ΔLMN ≅ ΔKMN
Cot(3x)=3^(1/2)
cot(x)= cos(x)/sin(x)
cot(3x)= cos(3x)/sin(3x)
look at a unit circle chart
find a value for cos that has sqrt(3) in it
which one will reduce so that the cos/sin will equal sqrt(3)?
pi/6 radians
now cot(3x) implies that x is one third this value
pi/18 is the answer
Answer:
809.4cm²
Step-by-step explanation:
Given the following :
Systematic error = 3.8cm (The measured length is always more than the actual length.)
Most probable dimension :
Width = 85.7 cm
Length = 123.5 cm
Hence most probable area of Rectangle :
Area = Length × Width
Area = 85.7cm × 123.5cm = 10583.95 cm²
Dimension due to Systematic error :
Length = (85.7cm + 3.8cm) = 89.5cm
Width = (123.5cm + 3.8cm) = 127.3cm
Area = Length × width
Area = ( 89.5cm × 127.3) = 11393.35cm²
Systematic error of the area :
value of area with Systematic error - Probable value of area :
11393.35cm² - 10583.95 cm² = 809.4cm²
Answer:
the answer is 10/22 when i calculated it
