Answer is: iron is oxidized to form rust.
Chemical reaction: Fe + O₂ → Fe₂O₃.
Oxidation half reaction: Fe⁰ → Fe⁺³ + 3e⁻ /×4; 4Fe⁰ → 4Fe⁺³ + 12e⁻.
Reduction half reaction: O₂⁰+ 4e⁻ → 2O⁻²/×3; 3O₂⁰+ 12e⁻ → 6O⁻².
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
Oxidation is increase of oxidation number, iron is oxidized from oxidation number 0 (Fe) to oxidation number +3 (in rust Fe₂O₃).
Explanation:im not really sure about this one but i think it is either c or b
ANSWER:C im pretty sure.sorry if wrong
Answer:
2.16 moles of Au₂S₃ are decomposed.
Explanation:
Given data:
Number of moles of gold (III) sulfide decomposed = ?
Number of moles of gold metal formed = 4.32 mol
Solution:
Chemical equation:
Au₂S₃ → 2Au + 3S
Now we will compare the moles of Au₂S₃ with gold metal.
Au : Au₂S₃
2 : 1
4.32 : 1/2×4.32 = 2.16
2.16 moles of Au₂S₃ are decomposed.
Fe
Cobalt
Sodium
Sn
Phosphorus
Florine
I don’t know
Mg
I don’t know
Calcium
C
Pb
Silver
Zinc
Nickel