Answer:
Atomic radius is directly proportional to Metallic reactivity in group 2.
Explanation:
Atomic radius is directly proportional to Metallic reactivity in group 2.
As we move down the group in group 2 which is called as the alkaline earth metals, the atomic number increases due to which the subshell increases. And the outermost shell's electron are less tightly held to the nucleus of the atom. Since the electrons are loosely held that means they can easily participate in reactions and that what makes it reactive down the 2nd group. Therefore alkaline earth metals with higher atomic number are more chemically reactive.
The most accurate means of determining the purity of a substance is through the use of analytical methods. These methods, widely used in different industries, mostly involve chemical analysis, which can pinpoint the presence, identity and amount of impurities in the sample. The most simple chemical methods include gravimetry and titration. There are also the more advanced light-based or spectroscopic methods, such as UV-VIS spectroscopy, nuclear magnetic resonance and infrared spectroscopy. Chromatographic methods, such as gas chromatography and liquid chromatography, can also be used. Other methods used in testing the purity include mass spectroscopy, capillary electrophoresis, optical rotation and particle size analysis.
-basically nerdy talk for using machines controlling chemicals or other atoms to pinpoint any impurities
B I think but not 100% sure
The answer is A. foliated
There can be two kinds of metamorphic rocks: foliated and non-foliated.
Foliated rocks are formed by intense pressure, squeezing their minerals so they become aligned. In contrast, non-foliated rocks do not form due to pressure.
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Answer:
The formula would be: C₆H₈O
Explanation:
The mass of carbon dioxide formed = 627.4 mg
The percentage of carbon in the sample would be:
% carbon = ![\frac{12Xmass of carbondioxideX100}{44Xmassofsample}=\frac{12X627.4X100}{44X228.4}=74.92](https://tex.z-dn.net/?f=%5Cfrac%7B12Xmass%20of%20carbondioxideX100%7D%7B44Xmassofsample%7D%3D%5Cfrac%7B12X627.4X100%7D%7B44X228.4%7D%3D74.92)
Where
44 is the molar mass of carbon dioxide.
The percentage of hydrogen in the sample would be:
% Hydrogen = ![\frac{2Xmassofwater}{18Xmassofsample}=\frac{2X171.2X100}{228.4X18}=8.33](https://tex.z-dn.net/?f=%5Cfrac%7B2Xmassofwater%7D%7B18Xmassofsample%7D%3D%5Cfrac%7B2X171.2X100%7D%7B228.4X18%7D%3D8.33)
Rest will be oxygen = 100 -[74.92+8.33]=16.75
Let us calculate the moles of each of the elements present:
moles of carbon = ![\frac{mass}{atomicmass}=\frac{74.92}{12}=6.24](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Batomicmass%7D%3D%5Cfrac%7B74.92%7D%7B12%7D%3D6.24)
moles of hydrogen = ![\frac{mass}{atomicmass}=\frac{8.33}{1}=8.33](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Batomicmass%7D%3D%5Cfrac%7B8.33%7D%7B1%7D%3D8.33)
moles of oxygen = ![\frac{massofoxygen}{atomicmass}=\frac{16.75}{16}=1.05](https://tex.z-dn.net/?f=%5Cfrac%7Bmassofoxygen%7D%7Batomicmass%7D%3D%5Cfrac%7B16.75%7D%7B16%7D%3D1.05)
The mole ration of carbon, hydrogen and oxygen = C:H:O = 6 : 8 : 1
so the formula would be:
C₆H₈O