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Katarina [22]
3 years ago
6

What is the total price of a 10000 car plus 7.5% sales tax

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0
Total price = Original price + (original price * sales tax decimal)

Total price = 10000 + (10000 * 0.075) 
= 10000 + 750

Your price on the car is 10,750
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Answer:-2,4 is the answer

Step-by-step explanation:

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Please find the function rule and explain how you got it so it helps me understand better. I am SO bad with function rules. ;-;
riadik2000 [5.3K]
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8 0
4 years ago
Ollie earns a fixed amount of $2,700 per month and a commission of 12% on all of his sales for the month. To cover all of his ex
storchak [24]

Answer:

Part A) 0.12x+2,700\geq 5,400

Part B) see the explanation

Step-by-step explanation:

Part A) Write an inequality that will represent the amount of sales Ollie will need in order to cover his monthly expenses

Let

x ----> the amount of sales monthly

Remember that

12\%=12/100=0.12

we know that

The fixed amount of $2,700 plus the commission of 12% on all of his sales for the month must be greater than or equal to $5,400

so

The inequality that represent this problem is

0.12x+2,700\geq 5,400

Part B) Find the solution and describe what the graph would look like on a number line

we have

0.12x+2,700\geq 5,400

Solve for x

subtract 2,700 both sides

0.12x \geq 5,400-2,700\\0.12x \geq 2,700

Divide by 0.12 both sides

x\geq \$22,500

The minimum amount of sales needed to cover his monthly expenses is $22,500

In a number line the solution is the shaded area at right of x=22,500 (closed circle)

see the attached figure to better understand the problem

4 0
3 years ago
Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. A(1,0), B(3,6), C(-1,4)
Karo-lina-s [1.5K]

Answer:

45°, 45°, 90°

Step-by-step explanation:

Find the vectors to represent each sides

AB =<3-1, 6-0>=<2,6>  

AC = < -1-1, 4 - 0 > = < -2, 4>

Magnitude of the vectors

AB = √(2²+6²) = 6.32

AC = √ ((-2)² + 4²) = 4.47

cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504

θ = arcos(20 / 28.2504 ) approx = 45°

Magnitude of the vectors

BA =<1-3,0-6>=<-2,-6>

BC =<-1-3,4-6>=<-4,-2>

Magnitude of the vectors equals

BA = √((-2)² + (-6)²) = 6.325

BC = √((-4)² + (-2)²) = 4.4721

cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286

θ  = arcos (20 / 28.286 ) = 45°

Magnitude of the vectors

CB =<3--1, 6-4>=<4,2>

CA=<1--1,0-4>=<2,-4>

Magnitude of the vector =

CB = √(4² + 2²) = 4.4721

CA = √(2² + (-4)²) = 4.4721

cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0

θ = arcos 0 = 90°

4 0
3 years ago
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