Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
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Answer: 
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3*sqrt(7)
3 times the square root of 7
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Explanation:
I'm assuming the V stands for square root. You can write sqrt(63).
The idea is to factor 63 in such a way that one factor is the largest perfect square possible, that way we can pull the root apart to simplify as shown above. The rule I used for the second step is 
Answer:
24$
Step-by-step explanation:
If she ended with 12 $ and she spends half of her money on the mini golf it means that you need to multiply 12 by 2 and you will get 24.
So it would be y=3+5 so you really just add 3+5 and that’s 8 so it would be y=8
Answer:
Step-by-step explanation:
Equilateral triangles have equal sides.
Two sides are equal, so we can put up an equation to solve for 
.
Let's solve for one side of the triangle.
