All u have to do is plug in the values
68) -(4q) = -(4*-3) =-4*3= -12
70) 5P-6= (5*5)-6 =25-6= 19
72) 7q-7p= 7(-3)-7(5) = -21-35= -56
74)2q/(4p) = 2(-3)/4(5)= -6/20= -3/10
Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
Answer:
How many students like only tennis and football?
13 who like tennis and football
How many students like only baseball and football?
26 who like baseball and football
Answer:
18.15
Step-by-step explanation:
55% = 55/100
33 = 33/1
33/1 x 55/100
33 x 55 = 1815
1 x 100 = 100
1815/100 = 18.15
