All categories

3 years ago

Question's in attachment

Mathematics

2 answers:

vampirchik [111]3 years ago

5 0

Answer:i got 2.5 with the exes

but i got mean=6 with doing 4,5,6 and 9 and the median of those is 5.5 which is an answer choice on the paper

im pretty sure its 2.5 because that is with the data given but i dont see it as an answer choice thats why i told you the other answer

Step-by-step explanation:to get the mean you get the sum of the numbers divided by the count the sum in this particular example was 10 and the count 4 because of the rows so 10/4=2.5

Licemer1 [7]3 years ago

3 0

Answer:

3+4+2+1 = 10

----

1.6

Step-by-step explanation:

You might be interested in

Help me heeeeeeeeeeeeeeeeeeeeelllllllllpppp

borishaifa [10]

Answer:

The diameter would also double

Step-by-step explanation:

3 0

3 years ago

Directions: Simplify the following monomials.SHOW THE STEPS!

Pavel [41]

Answer:

I hope you enjoy it if you have any questions ask me

4 0

3 years ago

Read 2 more answers

Subtract: (b^2 + 9 ab + 5a ) - ( 3b^2 -25ab + 1)

Brrunno [24]

Answer:

- 2b^2 + 34ab + 5a - 1

Step-by-step explanation:

here's your solution

=> (b^2 + 9ab + 5a) - (3b^2 - 25ab + 1)

=> b^2 + 9ab + 5a - 3b^2 + 25ab - 1

=> - 2b^2 + 34ab + 5a - 1

hope it helps

6 0

3 years ago

Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x

mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;