Answer:
Step-by-step explanation:
If k is the number of classes and n is the number of observations, then for number of classes we should select the smallest k such that 2^k > n.
<u>We have n = 50 and:</u>
- 2^5 = 32 < 50
- 2^6 = 64 > 50
As per above described 2 to k rule, we are taking k = 6.
So 6 classes should be used.
Answer:
Probabilty of first component drawn defective= 0.1161
Probability of second component drawn defective= 0.1560
Step-by-step explanation:
Total component = 9
Defective component= 3
Non-defective component= 6
Probability of defective= 3/9
= 0.3333
Probabilty of non defective= 1-0.3333
= 0.6666
Probabilty of first component drawn is defective
= 9C1(0.333)¹(0.6666)^8
= 9(0.3333)(0.0387)
= 0.1161
Probabilty of second component is defective
= 8C1(0.3333)¹(0.6666)^7
= 8(0.3333)(0.0585)
= 0.1560
Answer:
2 and 3
Step-by-step explanation:
9/4=2.25
Answer:
It should be 2
Step-by-step explanation:
I searched it up