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Makovka662 [10]
3 years ago
5

What is a frequency in physics ?

Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

Frequency, in physics, the number of waves that pass a fixed point in unit time; also, the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.

Explanation:

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Hitting the brakes

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An element with 1 valence electron has a charge of
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<span>An element with 1 valence electron has a charge of -1, because there is an extra negatively charged electron attached to the ion.</span>
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4 years ago
An infinitely long line of charge has a linear charge density of 7.50×10^−12 C/m . A proton is at distance 14.5 cm from the line
Nata [24]

Answer:

10.22 cm

Explanation:

linear charge density, λ = 7.5 x 10^-12 C/m

distance from line, r = 14.5 cm = 0.145 m

initial speed, u = 3000 m/s

final speed, v = 0 m/s

charge on proton, q = 1.6 x 10^-19 C

mass of proton, m = 1.67 x 10^-27 kg

Let the closest distance of proton is r'.

The potential due t a line charge at a distance r' is given  by

V=-2K\lambda ln\left (\frac{r'}{r}  \right )

where, K = 9 x 10^9 Nm^2/C^2

W = q V

By use of work energy theorem

Work = change in kinetic energy

qV = 0.5m(u^{2}-v^{2})

By substituting the values, we get

V=\frac{mu^{2}}{2q}

-2K\lambda ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{2q}

- ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{4Kq\lambda }

- ln\left ( \frac{r'}{r} \right )=\frac{1.67 \times 10^{-27}\times 3000\times 3000}{4\times 9\times 10^{9}\times 1.6\times 10^{-19}\times 7.5\times 10^{-12} }

- ln\left ( \frac{r'}{r} \right )=0.35

\frac{r'}{r} =e^{-0.35}

\frac{r'}{r} =0.7047

r' = 14.5 x 0.7047 = 10.22 cm

5 0
3 years ago
A person with Parkinson's disease may sometimes experience muscle tremors and difficulty initiating movements or speech. To help
Ulleksa [173]

Answer:

dopamine is used to help with Parkinson

Explanation:

D. dopamine

3 0
3 years ago
Work out the following a) Find β = v/c for a person walking at 3 mile/hr and a truck moving at 65 mile/hr. (b) Find γ-1, where γ
balu736 [363]

Explanation:

It is given that,

Speed of the person, v = 3 mile/hr = 1.34 m/s

Speed of the truck, v' = 65 mile/hr = 29.05 m/s

(a) Since, \beta =\dfrac{v}{c}

For the person, \beta =\dfrac{1.34}{3\times 10^8}=4.47\times 10^{-9}    

For the truck, \beta =\dfrac{29.05}{3\times 10^8}=9.68\times 10^{-8}

(b) The relativistic factor is given by :

\gamma=\dfrac{1}{\sqrt{1-\beta^2}}

For very small velocity, \beta

\gamma=(1-\beta ^2)^{-1/2}\approx 1+\dfrac{1}{2}\beta ^2

\gamma-1=\dfrac{\beta^2}{2}

For the person :

\gamma-1=\dfrac{(4.47\times 10^{-9})^2}{2}=9.99\times 10^{-18}

For the person :

\gamma-1=\dfrac{(9.68\times 10^{-8})^2}{2}=4.68\times 10^{-15}

Hence, this is the required solution.

3 0
3 years ago
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