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Elenna [48]
2 years ago
12

The figure below shows a motorcycle leaving the end of a ramp with a speed of 39.0 m/s and following the curved path shown. At t

he peak of the path, a maximum height h above the top of the ramp, the motorcycle's speed is 37.1 m/s. What is the maximum height h? Ignore friction and air resistance. (Enter your answer in m.)
_____m

Physics
1 answer:
lisov135 [29]2 years ago
7 0

The maximum height h of the curved path is 7.38 m.

<h3>Maximum height of the curved path</h3>

Apply the following kinematic equation;

v² = u² - 2gh

where;

  • v is the final velocity of the motorcycle
  • u is initial velocity of the motorcycle
  • h is the maximum height

(u² - v²)/2g = h

(39² - 37.1²)/(2 x 9.8) = h

7.38 m = h

Thus, the maximum height h of the curved path is 7.38 m.

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

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4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx
frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

Ix=.\frac{Req}{Rx} *Itotal (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2}  } (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

Req.=\frac{ 100*R1}{R1+100} (3)

Now substituting (3) in (1).

25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

7 0
3 years ago
Kilo-  -  1,000<br>deka-  -  10<br><br>How much larger is a kilo- than a deka-?
Ilya [14]
lets's \ take \ an \ example \ one \ gram: \\ \\ 0,001kg \\ \\ 0,01hg \\ \\ 0,1dag \\ \\ \boxed{1g} \\ \\ 10dg \\ \\ 100cg \\ \\ 1000mg  \\ \\ the \ units \ are \ rising \ and \ decreasing \ from \ 10 \ to \ 10 \ results \ \\ \\ a \ kilogram \ is \ 100 \ times \ larger \ than \ a \ dekagram
6 0
2 years ago
Problem 12: A 20.0-m tall hollow aluminum flagpole is equivalent in strength to a solid cylinder 4.00 cm in diameter. A strong w
avanturin [10]

Answer:

The deformation in the pole due to force is 0.70 mm.

Explanation:

Given that,

Height = 20.0 m

Diameter = 4.00 cm

Force = 1100 N

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Using formula of area

A=\pi\times r^2

A=\pi\times(2.00\times10^{-2})^2

A=0.00125\ m^2

A=1.25\times10^{-3}\ m^2

We need to calculate the deformation

Using formula of deformation

\Delta x=\dfrac{1}{s}(\dfrac{F}{A}\times L)

Where, s = shear modulus

F = force

l = length

A = area

Put the value into the formula

\Delta x=\dfrac{1}{2.5\times10^{10}}\times(\dfrac{1100}{1.25\times10^{-3}}\times 20.0)

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3 0
3 years ago
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asambeis [7]

Answer:

neither be created nor destroyed

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When we say charge is conserved, we mean that charge can neither be created nor be destroyed similar to energy concept.

When any physical quantity is conserved it always means that its quantity was, is and will remain the same throughout the eternity. It can neither be created nor be destroyed but it can change from one form to another.

6 0
3 years ago
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Answer:

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5 0
3 years ago
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