Answer:
d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion
Explanation:
The speeds of the particles are very large and comparatively the average free path is very small . Therefore time taken in covering the free path ( path between two consecutive collision with medium particles ) is very small . Hence the st line path covered by particles between two collision is less likely to be visible. Hence motion appears irregular or zig-zag.
I think it’s 8 hours. I’m sorry if I’m wrong.
I just did 400 divided by 50
I think it’s C. Stroke if not then D
<u>Answer:</u> The Young's modulus for the wire is ![6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:
![Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7BF%2FA%7D%7B%5CDelta%20l%2Fl%7D%3D%5Cfrac%7BFl%7D%7BA%5CDelta%20l%7D)
where,
Y = Young's Modulus
F = force exerted by the weight = ![m\times g](https://tex.z-dn.net/?f=m%5Ctimes%20g)
m = mass of the ball = 10 kg
g = acceleration due to gravity = ![9.81m/s^2](https://tex.z-dn.net/?f=9.81m%2Fs%5E2)
l = length of wire = 2.6 m
A = area of cross section = ![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
r = radius of the wire =
(Conversion factor: 1 m = 1000 mm)
= change in length = 1.99 mm = ![1.99\times 10^{-3}m](https://tex.z-dn.net/?f=1.99%5Ctimes%2010%5E%7B-3%7Dm)
Putting values in above equation, we get:
![Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B10%5Ctimes%209.81%5Ctimes%202.6%7D%7B%283.14%5Ctimes%20%288%5Ctimes%2010%5E%7B-4%7D%29%5E2%29%5Ctimes%201.99%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5CY%3D6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
Hence, the Young's modulus for the wire is ![6.378\times 10^{10}N/m^2](https://tex.z-dn.net/?f=6.378%5Ctimes%2010%5E%7B10%7DN%2Fm%5E2)
Answer:
The correct answer is 24.
Explanation: