Answer:
•Determine your IP address.
•Verify physical connectivity to the network.
•Check that you have a logical connection to the network.
•Find out what path network traffic takes to get to its destination.
Translate from DNS names to IP addresses.
Answer:
the answer is computer, phone, laptop
Explanation: that is all ik
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
Answer:
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Explanation:
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Answer:
White, the color value is 0xFFFFFF
Explanation:
Each segment is 8-bits, which totals to 255 in base-10 value, or 0xFF in hexadecimal.
11111111₂ == 255₁₀ == 0xFF₁₆
so
Red Green Blue
11111111 11111111 11111111
FF FF FF
When all 3 color values are turned on at max value (255), they produce white.
