Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
e number. For example, if countLimit is 5 the expected output will be 0 1 2 3 4 5 import java.util.Scanner;
public class CountToLimit {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
countLimit = scnr.nextInt();
printVal = 0;
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( /* Your solution goes here */ );
System.out.println("");
return;
}
}
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with newline Ex: For the user input 123, 395, 25, the expected output is:
Enter a number (<100):
Enter a number (<100):
Enter a number (<100):
Your number < 100 is: 25
import java.util.Scanner;
public class NumberPrompt {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int userInput = 0;
/* Your solution goes here */
System.out.println("Your number < 100 is: " + userInput);