Here you go plz mark brainlist
Answer:
# Python program to shuffle a deck of card
# importing modules
import itertools, random
# make a deck of cards
deck = list(itertools.product(range(1,14),['Spade','Heart','Diamond','Club']))
# shuffle the cards
random.shuffle(deck)
# draw five cards
print("You got:")
for i in range(5):
print(deck[i][0], "of", deck[i][1])
Output
You got:
5 of Heart
1 of Heart
8 of Spade
12 of Spade
4 of Spade
Explanation:
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.
Answer:
import math
def rectangle(perimeter, area):
l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4
l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4
l2_1 = area/l1_1
l2_2 = area/l1_2
print(l1_1,l2_1)
print(l1_2,l2_2)
if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:
return(int(max(l1_1,l2_1)))
elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:
return(int(max(l1_2,l2_2)))
else:
return(None)
Explanation:
- We import math to make basic operations
- We define the rectangle function that receives perimeter and area
- We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
- We calculate the second root of the quadratic equation for the same side (l1_2)
- We calculate the second side of the rectangle using the first root on w = a/h
- We calculate the second side of the rectangle using the second root on w= a/h
- We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
- If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
- if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
