The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.
11. 2x+3x+1=21
5x+1 =21
5x=20
x=4
TU= 2(4) which is 8
UB= 3(4)+1 which is 13
12. 4x-1 +2x-1=5x
6x-2=5x
-2=-1x
2=x
X=2
TU= 7
UB= 3
TB=10
Problem 13:
2x-8=x+17
2x=x+25
x=25
AB =42
BC=42
AC=84
Problem 14:
3x-31
-x+6
=
2x-37 for BC part now we solve for x
x+6=2x-37
6=x-37
43=x
So :
X=43
AB=49
AC=98
BC=49
Answer:
7 / 15
Step-by-step explanation:
15x - 7 = 0
15x = 7
x = 7/15
Answer:
Step-by-step explanation:
2log(x-3)=log25
log(x-3)²=log25 cancel out log on both sides
(x-3)²=25
x²-6x+9=25
x²-6x+9-25=0
x²-6x-16=0 factorize
x²+2x-8x-16=0
x(x+2)-8(x+2)
(x-8)(x+2)=0
x-8=0 or x+2=0
x=8 or x=-2
x=-2 cannot be considered because of the -ve sign.
x=8.
check
2log(x-3)
2log(8-3)
2log5
log5²=25
therefore LHS=RHS
I will do my best to explain this “ x method “ I use
Basically, two factors of the first and last number must multiply together to sum up to equal the middle number
1 X 12
1 4
(x+12) (x+4)
Hope this helps!
