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Likurg_2 [28]
3 years ago
12

Need help with statistics please answer!

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

The city with the greater population density is <u>Chicago</u> because <u>2,700,000</u> > <u>440,000</u>

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Solve by elimination:<br> 2x + 4y = 34<br> x+4y = 27<br> A (7,-5)<br> B (6,6)<br> (7,5)<br> (5,7)
julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0
3 years ago
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I need help remember taking the square root of a number is the inverse/opposite of squaring number
kirill [66]
X will equal 4 because 4^2=4*4 which equals 16
8 0
3 years ago
Find the sum of the first 50 positive even integers.
adell [148]
2250
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50*102/2
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7 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
(30 POINTS AND BRAINLIEST) Show all work to solve 3x^2 + 5x − 2 = 0.
Dahasolnce [82]

Answer:

The answer to your question is:    (x + 2)(3x - 1) = 0

x1 = -2

x2 = 1/3

Step-by-step explanation:

                                           3x² + 5x − 2 = 0

Multiply 3 x -2 = -6

Find two numbers that added = +5 and multiply -6

These numbers are +6  and -1

Then:

                                           3x² + 6x -1x − 2 = 0

Factorize                           3x (x + 2) - 1(x + 2) = 0

Factorize again                (x + 2)(3x - 1) = 0

Finally

                         x + 2 = 0               3x - 1 = 0

                         x = -2                     x = 1/3

                                                   

5 0
3 years ago
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