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kolezko [41]
3 years ago
5

An athlete runs 8 miles in 50 minutes on a treadmill. At this rate, how long will it take the athlete to run 9 miles?

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0
I think it’s 56.25 mins
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What was done to the quadratic parent function F(x) = x2 to get the
zubka84 [21]

Answer:

Option C.

Step-by-step explanation:

If k<0, the function g(x) = f(x) + k represents the function f(x) shifted k units downwards.

In this case, given that k=-3 (k<0). The graph was shifted 3 units down. Therefore, the correct option is Option C.

5 0
3 years ago
Please help solve the problem below.
ivann1987 [24]

Answer:

1. x = 2

2. x = 5

3. x = 8

4. x = 28

5. x = 13

6. x = 11

7. x = 0

8. x = 72

9. x = 6

10. x = 38

Step-by-step explanation:

hope that helps!

1. subtract 6 on both sides

2. add 3 on both sides

3. divide both sides by 2

4. multiply both sides by 2

5. add 8 on both sides

6. subtract 9 on both sides

7. add 5 on both sides

8. multiply both sides by 6

9. divide both sides by 4

10. add 18 on both sides

3 0
3 years ago
Please help me!!! I will try to mark brainliest if the answer is correct!
netineya [11]

Answer:

I think the first is answer bcz 35+55=90 ..... 180-90=90

5 0
3 years ago
What is 5/8 as a decimal??
Angelina_Jolie [31]
5/8 as a decimal would be 0.625. :)
4 0
3 years ago
Read 2 more answers
Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de
Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=7\\\\H_a:\mu> 7

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25

The degrees of freedom for this sample size are:

df=n-1=49-1=48

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>5.25)=0.000002

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0
3 years ago
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