Question

What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?

Answer 1

Answer:

Diameter = 33 feet

Step-by-step explanation:

Diameter = 2 x radius

Given that the volume = 18174 $ft^{3}$, then;

Volume of sphere = $\frac{4}{3}$$\pi$$r^{3}$

where r is the radius of the sphere.

Thus,

18174 = $\frac{4}{3}$ x $\frac{22}{7}$ x $r^{3}$

         = $\frac{88}{21}$ $r^{3}$

18174 x 21 = 88 $r^{3}$

381654 = 88 $r^{3}$

$r^{3}$ = $\frac{381654}{88}$

   = 4336.9773

r = $\sqrt[3]{4336.9773}$

r = 16.3078

The diameter of the sphere = 2 x 16.3078

                                              = 32.6156

                                              = 33 feet