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2 years ago

7

. The graph below shows the relationship between the number of calories burned by William and the number of minutes he spends jo

gging. Based on the data, which of the following equations can be used to calculate the total calories William burns (y) if he jogs for (x) minutes? *

1 answer:

kogti [31]2 years ago

4 0

Answer:

C

Step-by-step explanation:

y = 20x because they asked what equation can be used to calcuate the total calories he will lose meaning 120 divided by 20= 6

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PLEASE I NEED HELP CLICK ON THIS IMAGE

Alecsey [184]

Answer:mean

Step-by-step explanation:

I would assume it’s the mean since that averages the 7 test scores it represents the data set well. Outlier and mode don’t describe a data set since they are quite unique within it.

7 0

3 years ago

Read 2 more answers

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago

BRAINLIEST FOR ANSWER WITH EXPLANATION<br> JUST ONE QUESTION ATTACHED BELOW:

skelet666 [1.2K]

Answer:

m=16

Step-by-step explanation:

(6+6)/m=6/8

12/m=6/8

M=16

3 0

3 years ago

Read 2 more answers

If (fx)=5x, what is f^-1(x)

zysi [14]

Answer:

x/5

Step-by-step explanation:

To get the inverse function you need to leave the x alone and then switch variables ( f(x) = y)

f(x) = 5x

y = 5x

y/5 = x

Now that x is alone you switch the x for y and the y for x and you get:

x/5 = y

And this new y is the inverse function of f(x) ( f^-1(x))

f^-1(x) = x/5

6 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

<em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using <em>factorization</em> method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using <em>factorization</em> method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is $2y^{2} (y+ 10)$ .

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

$HCF \times LCM = p \times q$

Using equations <em>(1)</em> and <em>(2)</em>: $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, <em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago