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oksian1 [2.3K]
3 years ago
12

Explain the bond formation of ocl2 molecule​

Chemistry
1 answer:
Jlenok [28]3 years ago
3 0

Answer is in the file below

tinyurl.com/wpazsebu

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<h3><em>The third energy level can actually hold up to 18 electrons</em></h3>

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Consider the reaction 2xy+z2⇌2xyz which has a rate law of rate= k[xy][z2] select a possible mechanism for the reaction.
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We can dictate the mechanism of the reaction by looking at the exponents of the reactants in the reaction rate equation. Since [xy] has an exponent of 1, then the reaction follows the first order reaction with respect to xy. Similarly, the reaction follows the first order with respect to z₂. Then, the overall is the sum of each of their orders which is 2.
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How many photons are produced in a laser pulse of 0.897 J at 407 nm?
Leona [35]
The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.

Before being able to solve for energy, need to convert nanometers to meters.

407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m

Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)

E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms

E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)

E = 4.89 x 10^-33 J

This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J

0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34

1.83435583 × 10-34m4 kg2 / s4 photons
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4 years ago
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The base is H2O because it is accepting an H+ ion.
5 0
3 years ago
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