The answer to this is Codon.
the calculated value is Ea is 18.2 KJ and A is 12.27.
According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.
At 500K, K=0.02s−1
At 700K, k=0.07s −1
The Arrhenius equation can be used to calculate Ea and A.
RT=k=Ae Ea
lnk=lnA+(RT−Ea)
At 500 K,
ln0.02=lnA+500R−Ea
500R Ea (1) At 700K lnA=ln (0.02) + 500R
lnA = ln (0.07) + 700REa (2)
Adding (1) to (2)
700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.
=ln [0.02/0 .07]
Ea= 2/35×100×8.314×1.2528
Ea =18227.6J
Ea =18.2KJ
Changing the value of E an in (1),
lnA=0.02) + 500×8.314/18227.6
= (−3.9120) +4.3848
lnA=0.4728
logA=1.0889
A=antilog (1.0889)
A=12.27
Consequently, Ea is 18.2 KJ and A is 12.27.
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The term "valence electrons" refers to all of the electrons in an atom's outermost shell.
The centre of the atom is where the nucleus is. The nucleus contains protons and neutrons. The electrons travel in a specific circular direction and at a specific distance from the nucleus.
The atom's final shell's electrons take part in chemical reactions and the production of bonds. Both ionic and covalent bonding involve valence electrons. Metals are elements with one, two, or three electrons in their final shell.
These substances become positive ions after losing their electrons. Non-metals are substances with 5, 6, or 7 electrons in the outermost shell. These substances all gain electrons and change into negative ions.
Ionic bonds are those created by the transfer of electrons between metals and non-metals. For instance, ionic bonding allows sodium and chlorine to interact to generate sodium chloride.
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Answer:
Density
Explanation:
Density is defined as the mass per unit volume. It is the ratio between the mass and the volume of a substance. It does not matter how large or small a sample of matter is, the same substance will always have the same density, because of this. The ratio between the mass and volume remains the same.
