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3 years ago

What name should be used for the ionic compound Pb(SO4)2

Chemistry

1 answer:

alexandr402 [8]3 years ago

3 0

Lead(II)Sulfate -- would have to be your answer

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g What would the [H3O ] be if you had a solution of 0.125 M solution of the zwitterionic form of Tyrosine

alexdok [17]

Answer:

b). It will have only one isoionic point which is found below pH = 7.0. c). It will be fully protonated at pH = 1.0 with a net charge of +2. d).

Explanation:

6 0

3 years ago

Liquid methylene bromide has a density of 2.50 g/mL. A barometer is constructed using methylene bromide instead of mercury. If t

vova2212 [387]

Answer:

393 cm

Explanation:

Step 1: Given and required data

Density of liquid methylene bromide (ρ): 2.50 g/mL (2.50 g/cm³)

Earth's gravity (g): 9.81 m/s²

Atmospheric pressure (P): 0.950 atm

Step 2: Convert 0.950 atm to Pa (N/m²)

We will use the conversion factor 1 atm = 101325 Pa.

0.950 atm × 101325 Pa/1 atm = 9.63 × 10⁴ Pa

Step 3: Convert 2.50 g/cm³ to kg/m³

We will use the conversion factors:

1 kg = 10³ g

1 m³ = 10⁶ cm³

$\frac{2.50g}{cm^{3} } \times \frac{1kg}{10^{3}g } \times \frac{10^{6}cm^{3} }{1m^{3} } = 2.50 \times 10^{3} kg/m^{3}$

Step 4: Calculate the height (h) of the liquid column

We will use the following expression.

P = ρ × g × h

h = P / ρ × g

h = 9.63 × 10⁴ Pa / (2.50 × 10³ kg/m³) × 9.81 m/s²

h = 3.93 m = 393 cm

7 0

3 years ago

The ____ Is trite with respect to its órbita plane by _____ degrees.

Aleonysh [2.5K]

Answer:

its the 80th degree .

Explanation:

3 0

4 years ago

Can anyone help me with this?

stiv31 [10]

Go To ScHoOl tO LeArN

8 0

4 years ago

If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg(OH)2, what is the concentration of the Mg(OH) 2 soluti

xenn [34]

2 HBr + Mg(OH) 2 yields Mg(Br) 2 + 2 H2O
M1V1 = M2V2
(0.245 M)(37.5 mL) = (M2)(18.0 mL)
9.1875 = (M2)(18.0 mL)
9.1875/(18.0 mL) = (M2)(18.0 mL)/(18.0 mL)
0.51041
this is not the complete answer as the mol to mol ratio must be considered!
For every 2 mols of HBr there is 1 mole of <span>Mg(OH)2; ratio = 2:1
</span>0.51041 / 2 = 0.25520
M2 = 0.25520
0.25520 M of<span> Mg(OH)2 solution</span>

7 0

3 years ago