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3 years ago

Select all the expressions that show the distance between points A and B.

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

Answer:

0 -1-(-8)

0-1=-1

-1-(-8)

-1+8

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Is f(x) = 10x2 + 10, x > 0 the inverse of g(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%20%5Cfrac%7Bx-10%7D%7B10%7D" id="T

agasfer [191]

Step-by-step explanation:

$x > - \frac{ 1}{5}$

6 0

3 years ago

10 - 4 (3-2y) = 8y -5

Lisa [10]

Answer:

No Solutions

Step-by-step explanation:

10 - 4(3-2y) = 8y - 5

Distribute:

10 - 12 + 8y = 8y - 5

Simplify:

-2 + 8y = 8y - 5

Same to both sides

-2 + 5 = 8y - 8y

3 = 0y

No Solutions

Let me know if you have any questions

8 0

3 years ago

Please get this problem correct. Please explain and make it easy to understand.

mezya [45]

9 is a solution.

Answer:

Solution given:

2x+10=28

subtracting both side by 10

2x+10-10=28-10

2x=18

dividing both side by 2

2x/2=18/2

x=9

4 0

3 years ago

Read 2 more answers

Any called luna with a friend called joabe carmo plzzzzzz say a word we are looking 4 u

omeli [17]

Answer:

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Write a quadratic function for each graph described.

user100 [1]

Answer:

$y=2x^2-\frac{4}{3}x-\frac{10}{3}$

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

we can write the equation of the parabola as

$y=a(x+1)(x-\frac{5}{3})$

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

$40=a(5+1)(5-\frac{5}{3})$

$40=a(6)(\frac{10}{3})$

$40=20a\\a=2$

substitute

$y=2(x+1)(x-\frac{5}{3})$

apply distributive property

$y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}$

see the attached figure to better understand the problem

6 0

3 years ago