The answer to this question is c. 2 3/4
Answer:
0.818335 ≤ p ≤ 0.86366
Step-by-step explanation:
Given that:
Sample size (n) = 1000
Positive lung cancer = 841
n(p) = 841, p(p) = 841/1000 = 0.841
n(1 - p) = 1000 - 841 = 159
1 - p = 0.159
95% confidence interval
For a 95% confidence interval : z = 1.96
P ± z√p(1-p) / n
0.841 ± 1.96 * √0.841(0.159) / 1000
0.841 - (1.96 * 0.0115636) = 0.818335344
0.841 + (1.96 * 0.0115636) = 0.863664656
0.818335 ≤ p ≤ 0.86366
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