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IrinaVladis [17]
3 years ago
14

Simplest form 7/15 - 1/5

Mathematics
2 answers:
Lunna [17]3 years ago
8 0

Answer:

4/15

Step-by-step explanation:

7/15 - 3/15 = 4/15

tekilochka [14]3 years ago
4 0

Answer:

4/15

Step-by-step explanation: i did the math

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Find x and y…………….????????
emmasim [6.3K]

Answer:

let \:  \alpha  \: be \: the \: 45 \\  \tan( \alpha )  =  \frac{p}{b} \\  \tan(45)  =  \frac{x}{3 \sqrt{2} } \\ 1 =  \frac{x}{3 \sqrt{2} }  \\ x = 3 \sqrt{2}  \\ by \: using \: pythagoras \: therom \\  {y}^{2}  =  {3 \sqrt{2} }^{2}  +  {3 \sqrt{2} }^{2}   \\ {y}^{2}  = 18 + 18 \\ y =  \sqrt{36}  \\ y = 6

Step-by-step explanation:

hope this will help you

8 0
2 years ago
A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.
baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}

<h3><u>Solution:</u></h3>

Given that  

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.  

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052

Similarly Amount earned by plant after three years =80 \times 1.05^{t}

\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is \mathrm{A}(t)=80 \times 1.05^{t}

5 0
3 years ago
A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f
max2010maxim [7]

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

  • x = kilograms of the 40% chocolate.
  • y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

8 0
1 year ago
Jodi Poured herself a cold soda that had an initial temperature of 37°F and immediately went outside to sunbathe where the tempe
quester [9]
I'm pretty sure it's 50°f because the original temperature is 37°f and after 8 minutes it was 42°f and 42 minus 37 is 5, 8 divided by 5 is 1.6 and then multiply that by 5 is 8 and 42 + 8=50°F
6 0
3 years ago
Outside a home there is a keypad that will open the garage if the correct four-digit code is entered.
dybincka [34]

Answer:

a: 210 codes are possible.

b: 1/210 is the probability of entering the correct code.

3 0
3 years ago
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