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leonid [27]
3 years ago
6

What’s the square root of 81

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

The square root of 81 is 9

Wittaler [7]3 years ago
5 0

The Square root of 81 would be 9.

Hope this helps, have a great day!

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Three students earned $48.76 at the bake sell. The students split the earnings evenly, how much did each student recieve?
Sveta_85 [38]

Answer

Find out the  how much did each student recieve .

To prove

Let us assume that  each student earned in the bake sell be x .

As given

Three students earned $48.76 at the bake sell.

The students split the earnings evenly i.e earning is divided into three equal parts .

Than the equation becomes

x = \frac{48.76}{3}

Solving the above

x = $16.25(approx)

Therefore the  each student recieve $16.25(approx) .

Hence proved


4 0
3 years ago
Read 2 more answers
A person invests 6500 dollars in a bank. The bank pays 6.5% interest compounded annually. To the nearest tenth of a year, how lo
slamgirl [31]
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3 years ago
The following are daily outputs from shift A and shift B at a factory.
Airida [17]

Answer:

shift B

Step-by-step explanation:

shift a is 78.6 repeating

shift b is 79.3 repeating

mean is when you add them all then divide it by the numbers it has

7 0
3 years ago
Simplify <br><br> -2i sq.root -12
Darina [25.2K]

Answer:

= 4sqrt3

Step-by-step explanation:

-2i sqrt -12

= -2i * i sqrt12 <-- i^2 = -1

= -2i^2sqrt12

= -2(-1)sqrt12

= 2sqrt12

= 2 * 2 sqrt3

= 4sqrt3

6 0
2 years ago
A pressure of a gas at 22°C is 600 mmHg when it occupies 2.5 L. If the gas is compressed to 1.8 L and the pressure changes to 76
zhuklara [117]

APPLICATION OF COMBINED GAS LAW

Combined gas law is a combination of Boyle's, Charles', and Gay-Lussac's Laws that expresses the relationship between pressure, temperature, and volume in a constant amount of gas (moles).

<u>Note:</u>

  • In solving any problems related to Gas Law, it is important to remember that the standard unit measure for the temperature is always expressed in Kelvin (K). To do so, whatever the given temperature is (either °C or °F) you should convert them first so computation will be efficient.
  • If the given is in °C, then use the formula \sf{K = °C + 273.15}
  • And if °F, \sf K =  \frac{5}{9} (°F - 32) + 273.15

So to answer your question, what is the new temperature in K, the new temperature is T2 = 269.176 K or 269.18 K

(Please see attached image for the solution).

6 0
2 years ago
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