Answer:
456
Step-by-step explanation:
11.5 oz would be 2 standard deviations below the mean... z -score = -2 = .0228 (from Z-Score table)
22.8% of 2000 = 456
Answer:
We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 31.7 milligrams
Sample mean,
= 28.5 milligrams
Sample size, n = 9
Alpha, α = 0.05
Sample standard deviation, s = 2.8 milligrams
First, we design the null and the alternate hypothesis

We use One-tailed t test to perform this hypothesis.
Formula:

Putting all the values, we have

Now,
Since,
We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.
lets say there are 100 girls.
4/5 of 100 is 80, so 80 girls have brown hair.
3/4 of the 80 who have brown hair have long hair.
3/4 of 80 is 60.
so we know that out of 100, 60 have long brown hair.
in simplest fraction form, 60/100= 3/5
Answer:
B
Step-by-step explanation:
X= 2 over 9 or in decimal form 0.2222....