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erastova [34]
2 years ago
13

Which expression represents the statement "12 divided by 3, then add 5"?

Mathematics
2 answers:
Dovator [93]2 years ago
8 0
The answer is C. 12/3 +5
12/3= 4
4+5 =9
Sholpan [36]2 years ago
4 0
For the first question it would be,
C.


0.5 x 1.24 = 0.62
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What is the domain of the function y =<br> x +4?
Sever21 [200]

all real numbers is the domain of the function y=x+4

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3 years ago
B is the midpoint of AC, AB=5x and BC=2x+9 find AB,BC, and AC
german

Answer:

Step-by-step explanation:

5x  = 2x + 9

3x = 9

x = 3

AB= 5(3)= 15

BC= 2(5) + 9= 10 + 9 = 19

AC= 15 + 19 = 34

8 0
3 years ago
How.to express the sum 21/9 in a whole number and fractions
JulijaS [17]

Answer:

2 1/3

Step-by-step explanation:

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8 0
2 years ago
Can somebody help me with this problem .. I’ll really appreciate it .
Ira Lisetskai [31]

Answer:

4(4x+3)=19x+9-3x+3

4*4x  4*4 =19x+9-3x+3

16x+12= 16x+12

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8 0
2 years ago
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4        

7 0
1 year ago
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