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blsea [12.9K]
3 years ago
15

Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from

the line at points F and E to form an isosceles triangle with point D. Angle DEF measures 75°. What is the measure of angle CFD?
Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer:

\angle CFD =105^o

Step-by-step explanation:

Given

\angle D FE = \angle DE F = 75^o

See attachment

Required

Determine the measure of \angle CFD

\angle CFD and \angle DFE are on a straight line.

So:

\angle CFD + \angle DFE = 180^o --- angle on a straight line

Substitute known values

\angle CFD + 75^o = 180^o

Collect like terms

\angle CFD =- 75^o + 180^o

\angle CFD =105^o

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