Question

Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from the line at points F and E to form an isosceles triangle with point D. Angle DEF measures 75°. What is the measure of angle CFD?

Answer 1

Answer:

$\angle CFD =105^o$

Step-by-step explanation:

Given

$\angle D FE = \angle DE F = 75^o$

See attachment

Required

Determine the measure of $\angle CFD$

$\angle CFD$ and $\angle DFE$ are on a straight line.

So:

$\angle CFD + \angle DFE = 180^o$ --- angle on a straight line

Substitute known values

$\angle CFD + 75^o = 180^o$

Collect like terms

$\angle CFD =- 75^o + 180^o$

$\angle CFD =105^o$