If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
C im pretty sure
Step-by-step explanation:
Because the square taken out has a 4x4 area which is 16 and the area of the whole square used to be 14x14 which is 196 and if u subtract 16 from that you get 180
Answer: 42.0
Step-by-step explanation:
Answer:
1 hot dog costs $0.75
1 bratwurst costs $1.35
Step-by-step explanation:
Let x and y be the price per dozen of hot dogs and bratwursts respectively.
The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60
8x + 13y = 282.60
The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00
10x + 15y = 333
and we have the linear system
<em>8x + 13y = 282.60
</em>
<em>10x + 15y = 333
</em>
which can be written in matrix form as
The solution would be given by
We have
hence
Now,
if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75
if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35
It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class
100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)
