What you are doing wrong is that you are using the formula to find the area of the entire circle rather than using the formula to find a sector of a circle. The two cases uses 2 different kind sentences of formulas.

3 0

3 years ago

What is the volume of this cone? Use 3.14 for pi and round your answer to the

emmasim [6.3K]

So I use the formula hopefully these steps work

7 0

2 years ago

Simplify 28/184 by reducing to lowest form<br> A) 1/46<br> B) 1/7<br> C) 14/92<br> D) 7/46

Elodia [21]

It’ll be D) 7/46 you can reduce it by dividing everything with 4

5 0

3 years ago

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

$x^2+8x-65=0$

Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

6 0

3 years ago