Y-(-7)=-9(x-6)
Y+7= -9x+54
Subtract 7 from both sides
Y= -9x+47
Answer:
Angle DCA = Angle CAB. (Alternate Interior Angle)
Angle DCA = 68°
Angles(DCA + ACB + BCE) = 180°. (Linear Pair)
Angle ACB + 68° + 33° = 180°
Angle ACB = 79°
Therefore,
Angle ABC = 33°. (Alternate Interior Angle)
Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula

As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula

Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .