Ask question

Ask question

All categories

3 years ago

6

A circle is centered on point B. Points A C and D lie on its circumference.

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

Step-by-step explanation:

If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle So, ADC = 124/2 => ⛰ ADC = 62

You might be interested in

GRADE 9 MATH TEXTBOOK QUESTION PLEASE HELP ME someone help me answer all of question 4??? ASAPP

oksano4ka [1.4K]

ANSWER:
A c) -2 1/5
B e) -1 1/3
C b) -0.7
D a) 3/2
E d) 14.5

Hope it helps u!

7 0

3 years ago

There are 160 pink and blue balloons at the party store. 56 of the balloons are blue. What percentage of the balloons are pink?

bazaltina [42]

160 - 56 = 104 pink ballons

104/100 = 13/125

4 0

4 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers

What's the answer to this question because we haven't yet went over this in class but I'm trying to be ahead and figure out how

eimsori [14]

When two parallel lines are intersected by another straight line, the inner angles are = 180

so (20x+5) + (24x-1) = 180

solve from there

4 0

4 years ago

I need help. How do I do this??

Ivenika [448]

First of all, you figure out that -4 < 3, so you use the first function definition. Then you put -4 wherever you see x.
.. f(-4) = (-4)^2 -5
.. = 16 -5
.. f(-4) = 11

3 0

3 years ago