Answer:
(2 , 3)
Step-by-step explanation:
Lines intersection is the solution
1) Look for common factors. You see that y^2 is a factor of every term so you can remove it to get
... = (y^2)(3x^2 -2x -8)
The quadratic in x can be factored by your favorite method. There is one called by various names that has you look for factors of (3)(-8) that add to (-2). When the quadratic is written as ax^2+bx+c, you're looking for factors of the product "ac" that add to "b". Of course, you know that
... -24 = -24*1 = -12*2 = -8*3 = -6*4
the last factor pair shown here has a sum of -2, so our factorization is
... = (y^2)(3x -6)(3x +4)/3 . . . . . the "a" coefficient is repeated in each factor (at first), then divided out
... = (y^2) (x -2) (3x +4)
2) You recognize this expression to be of the form
... (x +a)^2 = x^2 +2ax + a^2
where a=5. As a result, you know the factorization is
... = (x +5)^2
3) You recognize this expression to be the difference of squares, so you know the factorization is
... a^2 - b^2 = (a -b)(a +b)
where a=x and b=6. As a result, you know the factorizatin is
... = (x -6) (x +6)
Answer:
1
Step-by-step explanation:
"m" is the number in front of x and in this case it would be one (x times 1 is x)
Add 8 to both sides (-5)
-8 is going to cancel out so it will get ride of -8 and it will only add -5
-5+8=3
then all you have left is x
so it would be x=3
Answer:
(x-2)^2 +(y+5)^2=4^2
Step-by-step explanation:
x minus 2 squared + y plus 5 squared = radius squared