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zysi [14]
3 years ago
6

The map shows the location of four places in a city.

Mathematics
2 answers:
hammer [34]3 years ago
5 0

Answer:

(-2, 4) is also in the second quadrant

Step-by-step explanation:

The library is in the second quadrant, at the point (-3, 5), where the x-coordinate is negative and the y-coordinate is positive.  Among the four given points, only (-2, 4) is also in the second quadrant.

Vladimir79 [104]3 years ago
4 0

Answer:

if Eric house is in the same quadrant as the library then the coordinates will be (-2,4)

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15 customers entered a store over the course of 12 minutes. At what rate were the customers entering the store in minutes per cu
Feliz [49]

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3 costumers per minutes

Step-by-step explanation:

6 0
3 years ago
You are saving for a skateboard. Your aunt gives you $45 to start and you save $3 each week. The expression 45 + 3w gives the am
Kryger [21]

Answer:

105 dollars saved

Step-by-step explanation:

She only gave you 45 to start 3 times 20 is 60+45=105

3 0
3 years ago
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Lindsay has 3 3/4 gallons of paint plans on using 1 1/4 gallons in each row how many rooms should be able to paint
babunello [35]

Answer:

3 rooms

Step-by-step explanation:

1 1/4x3=3 3/4

or...

3 3/4 divided by 1 1/4 = 3

8 0
3 years ago
The pound has three kinds of dogs: pit bull, chihuahuas and mutts. All but 23 of the dogs are pit bull, all but 17 are chihuahua
Georgia [21]

Answer:

There are 68 dogs in the pound.

Step-by-step explanation:

Number of pit bull dogs in a pound = P = 23

Number of chihuahuas dogs in a pound = C = 17

Number of mutts dogs in a pound = M = 28

Total number of dogs in a pound = T

T = P+C+M=23+17+28=68

There are 68 dogs in the pound.

5 0
3 years ago
Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa
Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) :x^2+y^2+4z^2=36

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

\nabla f(x,y,z)=\\\nabla f(x,y,z)=

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)

So, 2x=-4\lambda

\Rightarrow x=-2\lambda

2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda

Substitute the value of x , y and z in the ellipsoid equation

(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2

With \lambda = 2

x=-2(2)=-4

y=2

z=2

With\lambda =- 2

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

7 0
3 years ago
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