Answer:
Step-by-step explanation:
Given that
To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector
At the particular point, r'(t) = (1,1,e)
Tangent vector = 
ii) Normal vector
T'(t) = 
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
= ![\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%26e%5Et%5C%5C0%260%26e%5Et%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%20e%5Et%28i-j%29)
Answer:
Step-by-step explanation:
hello :
g√ 108 =√ 3/g means : g² = √ 3/√ 108
g² = √(3/108)
g² = √(1/36)
g² = √(1/6)²
g² = 1/6
g = 1/√6 or g = - 1/√6
Answer:
the answer is B
Step-by-step explanation:
please makr brainliest
X = 25, y = 14.
This is possible to solve because the vertical angles (7y and 5y + 28 ; 3x +7 and 4x - 18) are equal to each other. To solve for x, just set the two x equations equal to each other. The same is done for y with the y equations.
