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Juli2301 [7.4K]

4 years ago

14

DNS ~ ARH What is the value of x?

1 answer:

ZanzabumX [31]4 years ago

6 0

<span><span>Corresponding angles are congruent (same measure)So in the figure above, the angle P=P', Q=Q', and R=R'.</span><span>Corresponding sides are all in the same proportionAbove, PQ is twice the length of P'Q'. Therefore, the other pairs of sides are also in that proportion. PR is twice P'R' and RQ is twice R'Q'.
so the value of x :
x / 110 = 21.6 / 72
solve for x
x = 33</span></span>

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Rewrite the following in ascending order.<br>9/25, 2/5, 14/-75, -19/10, 8/15

madam [21]

Step-by-step explanation:

Given numbers are 9/25 ,2/5, 14/-75, -19/10, 8/15

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LCM of the denominators = 150

9/25 = (9/25)×(6/6) = 54/150

2/5 = (2/5)×(30/30) = 60/150

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-19/10 = (-19/10)×(15/15) = -285/150

8/15 = (8/15)×(10/10) = 80/150

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3 0

3 years ago

given two terms in a geometric sequence find the 8th term and the recursive formula . a4=-12 and a5=-6

Crazy boy [7]

A geometric sequence is defined by a starting point, $a$ , and a common ratio $r$

The first term is $a$ , and you get every next term by multiplying the previous one by r.

So, our terms are

$\left[\begin{array}{c|c}a_1&a\\a_2&ar\\a_3&ar^2\\a_4&ar^3=-12\\a_5&ar^4=-6\end{array}\right]$

We can see that when we pass from $a_4$ to $a_5$ the number gets halved ( $-12 \mapsto -6$ )

This implies that the common ratio is $r = \frac{1}{2}$

So, the table becomes

$\left[\begin{array}{c|c}a_1&a\\a_2&\frac{1}{2}a\\a_3&\frac{1}{4}a\\a_4&\frac{1}{8}a=-12\\a_5&\frac{1}{16}a=-6\end{array}\right]$

So, we can derive the starting point from either $a_4$ or $a_5$ :

$\dfrac{1}{8}a = -12 \iff a = -12\cdot 8 = -96$

The sequence is thus

$\left[\begin{array}{c|c}a_1&-96\\a_2&-48\\a_3&-24\\a_4&-12\\a_5&-6\\a_6&-3\\\vdots&\vdots\end{array}\right]$

And the recursive formula is

$a_n = -\dfrac{96}{2^{n-1}}$

7 0

4 years ago