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Julli [10]
3 years ago
14

Please help. It’s my last one (:

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0
The triangle is isosceles as two of its sides are equal
⇒ Angles opposite equal sides are equal
⇒ 55°=55°
Now with the help of the Angle-Sum-Property of a Triangle,
⇒ 55°+ 55°+ x= 180°
= x= 180°- 110°
= x= 70°
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2/7 divided by 1/4 =
dem82 [27]

Answer: 8/7

Step-by-step explanation:

To solve 2/7 ÷ 1/4,

Step 1: rewrite as-

2/7 × 4/1

=8/7

I hope this is clear.

4 0
3 years ago
Solve the following inequality -6 > - 3c
Inessa05 [86]
Dividing both sides by-3
the division sign will still be the same
your answer is c>2
4 0
3 years ago
25
Cloud [144]
If you are asking if your work is good,thn yes,you are right

7 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
WILL MARK BRAINLIEST!!!!<br> What is the equation of the line shown in this graph?
Eduardwww [97]
Y=1 because no matter the x value y will be 1
7 0
3 years ago
Read 2 more answers
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