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3 years ago

True or false? If two triangles are congruent, then they can be moved so that

Mathematics

2 answers:

Genrish500 [490]3 years ago

5 0

Answer:

True

Step-by-step explanation:

Elena-2011 [213]3 years ago

4 0

Answer:

This is true.

Congruent triangles have the same shape and the same size. So, you can position them so that one is superimposed (line up perfectly) on the other.

You might be interested in

Determine how many solutions if correct bainliest

PolarNik [594]

Answer:

No solutions

Step-by-step explanation:

6x+2y=20

-3x-y=-4 (by rewriting)

6/-3 = 2/-1≠20/-4

-2=-2≠-5

So it has no solutions

5 0

3 years ago

What is the second step to solve this x/2-5=1

sveta [45]

Answer:

X = -3

Step-by-step explanation:

X/2-5 = 1

X/-3 = 1

Multiply both sides by -3 to isolate x

X = -3

5 0

2 years ago

Solve for the value of X.

Mkey [24]

The answer is 40°
i will tell you how,
Total angle sum of any triangle is 180°
∠A + ∠B + ∠E = 180°
70° + 80° + ∠E = 180°
solve for ∠E
∠E = 30°
Now solve use ∠BDE,
∠B + ∠D + ∠E = 180°
20° + 90° + 30° + x = 180° (in triangle DEB, ∠E = 30 + x ) (∠D is 90°)
solve for x
there fore, x = 40°

6 0

3 years ago

As a small step to save the environment, Luna came up with an idea for her sweet shop. In exchange for five eclaire boxes, that

svet-max [94.6K]

Answer: 15

Step-by-step explanation:

From the question, we can infer from the information given that:

5 eclaires boxes = 1 free eclaires box.

Therefore, to get the number of eclaires boxes that the kids will get if they bring 77 eclaires boxes, we have to divide 77 by 5 and this will be:

= 77 / 5

= 15.4

= 15

The group of kids will receive 15 free boxes

5 0

3 years ago

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation

7 0

3 years ago