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natka813 [3]
3 years ago
10

True or false? If two triangles are congruent, then they can be moved so that

Mathematics
2 answers:
Genrish500 [490]3 years ago
5 0

Answer:

True

Step-by-step explanation:

Elena-2011 [213]3 years ago
4 0

Answer:

This is true.

Congruent triangles have the same shape and the same size. So, you can position them so that one is superimposed (line up perfectly) on the other.

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Miles is planning to spend 2/3 as many hours Bicycling this week as he did last week is Miles going to spend more hours were few
Firlakuza [10]

Answer: Yes, He bicycled fewer in this week than last week.

Step-by-step explanation:

Let he bicycled x hours in the last week,

Then, According to the question,

\text{ He bicycled in this week} = \frac{2}{3} \text{ of the hours he bicycled last week} = \frac{2x}{3}

\text{ Since, }1 > \frac{2}{3}

\implies x > \frac{2x}{3}

\text{ He bicycled in the last week} > \text{ he bicycled in this week}

Hence, He bicycled fewer in this week than last week.


3 0
3 years ago
What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now.. with that template above in mind, let's see yours


\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

7 0
3 years ago
At the local sandwich shop, employees earn double time for any hours worked in addition to their regular 40-hour week. Last week
Ede4ka [16]
Double-time for overtime...so overtime pay is 2(8.50) = 17

40(8.50) + 9(17) = 340 + 153 = 493 <== pay for the week
6 0
4 years ago
Read 2 more answers
Which function is graphed?
Dimas [21]
I think A is the correct answer hope this helps
4 0
3 years ago
Consider a sequence given by the formula f(n) = 1 / 3 ^ n−1 starting with n = 1. Generate the first 5 terms of the
denpristay [2]

Answer:

Step-by-step explanation:

According to the formula we need to start from n = 1. So the first 5 terms of the sequence, will have the following values of n: 1,2,3,4,5

Now, we need to replace the values of n into the formula to get all the terms.

f(1) = 1/3 ^ 1-1 = 1/3^0 = 1.

This is because any number elevated to zero is always the unit, in this case, 1.

f(2) = 1/3 ^2-1 = 1/3 ^1 = 1/3

This, because any number elevated to 1, is always the same initial number.

f(3) = 1/3 ^3-1 = 1/3 ^2 = 1/9.

Because when the exponent is elevating a fraction number, the power goes to both numbers (numerator and denominator)

f(4) = 1/3 ^4-1 = 1/3 ^3 = 1/27.

f(5) = 1/3 ^5-1 = 1/3 ^4 = 1/81.

5 0
4 years ago
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