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o-na [289]
3 years ago
12

Find the surface area of this cube

Mathematics
1 answer:
igomit [66]3 years ago
6 0
Equation is 6x^2
6(4.8)^2
138.24
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Which statement describes the translation of y = −5(x + 2)2 − 3 from standard position?
GalinKa [24]
C: Moved down and to the left
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What is the domain of the function below? (0,2 (3,1) (5,2) (8,4)
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{0,3,5,8} ok  this0 is the an0sw0er
7 0
4 years ago
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You roll a 6 sided dice what is the probability of rolling a number greater than two and then rolling a number less than three
Alexandra [31]

First answer is 4 chances and second answer is 2 chances

5 0
4 years ago
Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (m
Genrish500 [490]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

6 0
3 years ago
Read 2 more answers
P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Mila [183]

Answer:

The polynomial is:

p(x) = -x^3 - 2x^2 + 5x + 6

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that x_1 = -3, x_2 = -1, x_3 = 2. Thus

p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)

p(x) = a(x - (-3))*(x - (-1))*(x-2)

p(x) = a(x+3)(x+1)(x-2)

p(x) = a(x^2+4x+3)(x-2)

p(x) = a(x^3+2x^2-5x-6)

Passes through the point (1,12).

This means that when x = 1, p(x) = 12. We use this to find a.

12 = a(1 + 2 - 5 - 6)

-12a = 12

a = -\frac{12}{12}

a = -1

Thus

p(x) = -(x^3+2x^2-5x-6)

p(x) = -x^3 - 2x^2 + 5x + 6

6 0
3 years ago
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