Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
1) <span>30x4 − 20x3 + 15x2
This is the answer to 1. Don't forget to rearrange the terms in ascending order. That can trip people up.
2) </span><span>x3 + 8x2 + 13
Don't forget to check the terms sign. The subtraction symbol switches them all. </span>
Recall the Laplace transform of a second-order derivative,
and the transform of cosine,
Here, both 
, so taking the transform of both sides of
gives
The answer is 99 your welcome
Pretty sure the answer is B The horizontal asymptote y = 10 means that the final concentration will always be greater than 10%.
Step-by-step explanation:
Since the 10 % solution that you're adding to the 30% solution is 10% acid when you add it to the 30 acid percent solution it would never decrease the acidity levels farther than 10 percent no matter how much you put because the solution your adding is at a 10% acidity and the other solution is 30% acidity and has a higher acidity level than the 10% so it could never go lower than the solution you are adding to it.
Really hope I did an okay job at explaining.
