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3 years ago

When dividing fractions it is most helpful to change a mixed number into a

Mathematics

1 answer:

Tpy6a [65]3 years ago

6 0

When dividing fractions it is most helpful to change a mixed number into an improper fraction.

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8. Calculate the amount of simple interest on $15,500 for 4 years at

kvasek [131]

Answer:

SI=PTR/100

SI=15500*4*6.5/100

SI=403000/100

SI=4030$

3 0

3 years ago

Help me I’m on gradpoint. I will mark you brainlest if you can also find the website to get all gradpoint answers!

AlekseyPX

Answer:

C. (1, 1, 2)

Step-by-step explanation:

Well plugging them in one by one.

x + y - z = 0

-1 + 2 - 4 = 0

no.... no it doesn't equal 0 so it isn't the solution

-1 + 0 - 2 = 0

nope it doesn't equal 0 so it's also not the solution

1 + 1 - 2 = 0

Yes! this could equal the solution so lets keep going down the line

3x - y + z = 4

(3*1) -1 + 2 = 4

Yes! this also is correct

I could keep talking and talking but yes, (1, 1, 2) is your answer

Hope this helps! <3

3 0

2 years ago

Briana is excited because she has just been hired by a family to babysit on Saturdays. She’s looking forward to earning some ext

alexandr402 [8]

List the hours from 1 to 8

Multiply the hours by how much she is paid per hour ( $12)

X: 1, 2, 3, 4, 5, 6, 7, 8

y: 12, 24, 36, 48, 60, 72, 84, 96

8 0

3 years ago

Is my answer and graph correct?

PIT_PIT [208]

Yes it is correct. You plotted the slope and initial rate value correctly and found the
point of intersection.

7 0

2 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

2 years ago