Answer:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
Explanation:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
if(Expression to be tested) {
code to execute
} else if(Expression to be tested) {
code to execute
}
you can have as many else ifs as you want. But that's what it looks like.
Answer:
//Here is the for loop in C.
for(n=10;n>0;n--)
{
printf("count =%d \n",n);
}
Explanation:
Since C is a procedural programming language.Here if a loop that starts with n=10; It will run till n becomes 0. When n reaches to 0 then loop terminates otherwise it print the count of n.
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{ // variables
int n;
// for loop that runs 10 times
// when n==0 then loop terminates
for(n=10;n>0;n--)
{
cout<<"count ="<<n<<endl;
}
return 0;
}
Output:
count =10
count =9
count =8
count =7
count =6
count =5
count =4
count =3
count =2
count =1
Level 5 ( Full Driving Automation ) Level 5 cars won't even have steering wheels or acceleration / braking pedals . They will be free from geofencing , able to go anywhere and do anything that an experienced human driver can do .
Pls follow me and Mark as brainlest!!! :-)
Answer:
Examples of modern applications include office suites, graphics software, databases and database management programs, web browsers, word processors, software development tools, image editors and communication platforms. System software. These software programs are designed to run a computer's application programs and hardware.
Explanation:
Hope this helps :)
Have an amazing day <3
Pls mark brainliest :p