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Delicious77 [7]
3 years ago
14

SOLVE THE SIMULATENOUS EQUATIONS Y=X-2 AND Y= 3X+5

Mathematics
1 answer:
natta225 [31]3 years ago
3 0

Answer: y = x-2

y = 3x + 5

x-2 = 3x+5

x+3x = 5+2

4x = 7

x = 7/4

y = x-2

y = 7/4 - 2

y = 7-8/4

y = -1/4

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Answer with work plssss
Inessa05 [86]

Answer:

2a^4b^6

Step-by-step explanation:

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6 0
3 years ago
PLEASE HELP WITH PART A AND B- PLEASE HAVE WORKKK I WILL MARK BRAINLIEST PLEASE HELP!
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Answer:

6 + 6 = 12 × 10 = ?? = 132 that would be just guess the other

4 0
3 years ago
A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches. 2 triangular sides have a base of
melisa1 [442]

Answer:

Answer:

a) The base of the rectangular pyramid shown has an area of

60 square inches

b) A triangular face with a base of 10 inches has an area of 28 square inches.

c) A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

a) Solving for question a, we were given the following parameters

A rectangular pyramid. The rectangular base has a length of 10 inches and a width of 6 inches

The formula used to calculate the rectangular base of a rectangular pyramid =

Length × Width

Where :

Length = 10 inches

Width = 6 inches

Rectangular base = 10 inches × 6 inches

= 60 inches²

Hence, the base of the rectangular pyramid shown has an area of 60 square inches

b) Solving for question b, we have the following values given:

2 triangular sides have a base of 10 inches and height of 5.6 inches.

First step would be to solve for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (10 inches × 5.6 inches) ÷ 2

= 56inches² ÷ 2

= 28 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 28 inches².

A triangular face with a base of 10 inches has an area of 28 square inches.

c) Solving for question c, the following parameters are given:

2 triangular sides have a base of 5 inches and height of 7.1 inches.

We would be to solving for one triangular side first.

The area of the one triangular side = (Base × Height) ÷ 2

= (5 inches × 7.1 inches) ÷ 2

= 35.5 inches² ÷ 2

= 17.75 inches²

Therefore, for the 2 triangular sides, since they have the same base and height, the other side as well would be 17.75 inches².

A triangular face with a base of 5 inches has an area of 17.75 square inches.

d) Solving for d, it is important to note that, a rectangular pyramid has 5 faces and they are: The rectangular base and 4 triangular faces

The formula for the total surface area of the rectangular pyramid is given as

Total Surface Area of the rectangular pyramid = Rectangular Base + Area of Triangular Side A + Area of Triangular Side B + Area of Triangular Side C + Area of Triangular Side D + Area of Triangular Side E

Total Surface Area of the Rectangular Pyramid = 60 inches² + 28 inches² + 28 inches² + 17.75 inches² + 17.75 inches²

Total surface Area of the Rectangular pyramid = 151.5 inches²

The total surface area of the pyramid is 151.5 square inches.

Step-by-step explanation:

BRAINLIEST PLEASE?

3 0
3 years ago
Please solve -3x+12=48
choli [55]

Answer:

x = 12

Step-by-step explanation:

-3x+12=48

      -12 -12

*subtract 12 from both sides

-3x = 36

-3x/3 = 36/3

*divide 3 from each sides

x = 12

4 0
3 years ago
Read 2 more answers
Which classification best represents a triangle with side lengths 6 cm 10 cm and 12cm ?
crimeas [40]
A scalene triangle..
6 0
3 years ago
Read 2 more answers
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