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2 years ago

Marina will attend choir practice for 2-

Mathematics

1 answer:

maw [93]2 years ago

7 0

Answer:

Step-by-step explanation:

1).2+24+3 = 29

2) 29 x 2 = 58

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2,759 divided by 89?

EleoNora [17]

Answer:

Step-by-step explanation:

I can't explain any further......

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2 years ago

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You have a cell phone that is 5 inches in height, 0.5 inches in width, and 2.5 inches in length, what is the surface area in sq

fenix001 [56]

Answer: 32.5sq in I believe

I multiplied all the sides (ex 0.5x2.5x2) and did that with all the other sides

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3 years ago

Question 20 need an answerw

max2010maxim [7]

Which one is question 20??

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3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago

Pwese help ill give brainlyest

Luda [366]

Answer:

y=(14-8x) divided by 2

Step-by-step explanation:

minus 8x from both side you get

2y=14-8x

then you divide by 2

y=(14-8x) divided by 2

thats the furthest it can be simplified

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2 years ago

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