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kow [346]
3 years ago
9

The figure below is composed of two quarter circles and one right triangle

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Step-by-step explanation:

it's probably A i guess.

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LUCKY_DIMON [66]
D) 35m is the answer
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Write the equation of the line in point-slope form that passes through (5, -1) and has a slope of 2/3
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Answer:

y-(-1)=2/3(x-5)

Step-by-step explanation:

Point slope form is

y-y_1=m(x-x_1) where m is the slope, x_1 is the x coordinate of a point that the line passes through, and y_1 is the y coordinate of a point the line passes through.

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y-(-1)=2/3(x-5)

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The area of a square is 9 centimeters squared (cm^2) If the sides of the square are doubled in length, what is the new area, in
Mice21 [21]

Answer:

The question says area of a square = 9 cm squared.

And they said if the sides are doubled in length what is the new length

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which should give you 81cm^2

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7 0
2 years ago
Read 2 more answers
Need help with 7A plz
Eduardwww [97]
A) area of square = base*height/////Triangle= 0.5*base*height

=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)

B) a^2+b^2=c^2 (pythagorean theorem)
   ((27^2/3)*(16^1/4))^2 +  (27^1/3)*(16^3/4)   
     (9*2=(18^2))=324 +  (3*8= 24^2)= 576
      324+576= 900
     (900)^1/2= 30
hypotenuse= 30

C)( a^2/3*b^1/2)= 36*2(two sides)= 72
    (a^1/3b^3/4)=24
    (a^2/3*b^1/4)= 18
  72+24+18+30(hypotenuse)= 144=perimeter
7 0
3 years ago
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