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inna [77]
3 years ago
11

Help Is it linear or exponential

Mathematics
1 answer:
Amanda [17]3 years ago
7 0
<h3><u>Explanation</u></h3>
  • Linear

Linear is a straight line. You might have heard of Linear Function.

y = mx + b

The equation above is slope-intercept form.

  • Exponential

Exponential is both increasing graph and decreasing graph depending on the coefficient.

<u>Exponential</u><u> </u><u>Equation</u>

<u>y =  {a}^{x}  \:  \:  \: (a > 0) \:  \: (a \neq1)</u>

Exponential Graph increases when a-term is greater or equal to 1.

Exponential Graph decreases when a-term is greater than 0 but less than 1.

From the equation, it is exponential of x-term as an exponent. The equation matches with exponential form.

<h3><u>Answer</u></h3>
  • Exponential
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What is the slope of the line that passes through (4,26) and (-45,22.)
dusya [7]

It is 1/11 or 4/44.

Explained:

This is because when you subtract 26 and 22 you get 4 and when you subtract 4 and -45. The 45 then becomes a positive since when you get a negative and a negative you get a positive. Then you simplify it by 11.

8 0
3 years ago
Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give
frutty [35]

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

  • we know that \frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)

g'(x) =e^{x^{3}}(3 x^{2})

g'(x) =3 x^{2} e^{x^{3}}

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

3 0
3 years ago
Quinton bought x number of shares for p dollars and paid a 0.5% commission. He sold the stock for y dollars and paid a flat fee
Ksju [112]

Answer:

y-(0.05xp+7)

Step-by-step explanation:-

As per the statement:

Quinton bought x number of shares for p dollars and paid a 0.5% commission

⇒0.05xp

It is also given that: He sold the stock for y dollars and paid a flat fee of $7.

⇒y-7

then;

Net proceeds is given as:

y-7-0.05xp = y-(0.05xp+7)

Therefore, Quinton's net proceeds algebraically is y-(0.05xp+7)

4 0
3 years ago
Solve for W!<br> W - 2.76 = 6.7
MariettaO [177]
W - 2.76 = 6.7

isolate the W by adding 2.76 to both sides of the equal sign

W - 2.76 (+2.76) = 6.7 (+2.76)

W = 6.7 + 2.76

W = 9.46

9.46 is your answer

hope this helps
4 0
3 years ago
Read 2 more answers
Cynthia Besch wants to buy a rug for a room that is 21 ft wide and 34 ft long. She wants to leave
Daniel [21]

Answer:

Dimensions of the rug = 13 ft × 26 ft

Step-by-step explanation:

Dimensions of the room = 21 ft × 34 ft

Area of the room = 21 × 34 = 714 ft²

Cynthia wants to leave a uniform strip of floor around the rug.

Let the width of the rug = x ft

Then the dimensions of the rug will be = (21- 2x)ft × (34 - 2x)ft

Area of the rug = (21 - 2x)×(34 - 2x) square feet

338 = (21 - 2x)×(34 - 2x)

338 = 714 - 68x - 42x + 4x²

4x² - 110x + 714 - 338 = 0

4x² - 110x + 376 = 0

2x² - 55x + 188 = 0

2x² - 47x - 8x + 188 = 0

x(2x - 47) - 8(x - 47) = 0  

(x - 4)(2x - 47) = 0

x = 4, \frac{47}{2}

For x = 23.5 area of the rug will be negative.

Therefore, x = 4 ft will be the width of the rug.

Dimensions of the rug will be 13 ft × 26 ft. 

7 0
3 years ago
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